WebDec 9, 2024 · Hence $\sec x =\dfrac{1}{\cos x} > \dfrac{1}{1-\frac{x^2}{2}+\frac{x^4}{24}}=1+\dfrac{x^2}{2}+\dfrac{x^4}{8}+O(x^6) > 1+\dfrac{x^2}{2}$ on $(-\frac\pi2,\frac\pi2)$. I'm quite sure the proof above is correct, but it's way too long for a simple question like this one, so I was wondering if there was a much cleaner, shorter … WebBest Answer. sec (x-pi/2) = sin (x/2) f (x)=sin (x/2) For this you use the chain rule. So first, take the derivative of the sin function and then multiply by the derivative of the inside. f' (x)= cos (x/2)* (1/2) Same process for the second derivative f …. View the full answer.

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WebWhere a derivative is requested, be sure to label the derivative function with its name using proper notation. Let f(x)= 5sec(x)−2csc(x). f ( x) = 5 sec ( x) − 2 csc ( x). Find the slope of the tangent line to f f at the point where x = π 3. x = π 3. Let p(z)= z2sec(z)−zcot(z). p ( z) = z 2 sec ( z) − z cot ( z). Web프리 대수학, 대수학, 삼각법, 미적분학, 기하학, 통계학 및 화학 계산기 단계적 shv nightforce scopes

derivative of-4sec^2x+6sec^4x

WebTo find the implicit derivative, take the derivative of both sides of the equation with respect to the independent variable then solve for the derivative of the dependent variable with respect to the independent variable. What is an implicit derivative? Implicit diffrentiation is the process of finding the derivative of an implicit function. Websecx ‚ 1 or secx • ¡1: The period of secx is precisely the same as that of cosx, which means that the period of secx is 2…. The function secx is an even function, and this is because cosx is an even function. Finally, at every value of x not in the domain of secx, the function has both left and right vertical asymptotes. If a =:::;¡3 ... shv nightforce price